“The angle of the depression of boat A from the top of a cliff which is 2415. The angles depression of boat B from the same point is 1812. Find the distance between the two boats.”



The angle of the depression of boat A from the top of a cliff which is 2415. The angles depression of boat B from the same point is 1812. Find the distance between the two boats.

Answer:

d = 0.01⁰

Step-by-step explanation:

CONVERT DEGREES, MINUTES, SECONDS TO DECIMAL DEGREES

24” 15’ = 0.256⁰

18”12” = 0.005⁰

Solve:

Find the distance

tan

tan 0.256 = 0.005

                       d

tan 0.256 = 0.261 or 0.262 (round off)

0.262/1 = 0.005/d

= 0.005 . 1/0.262 = d/0.005 . 0.005

*Cancel 0.005 over d then times 0.005 to 1 then divide to 0.262

d = 0.01⁰


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